Solution Manual Heat And Mass - Transfer Cengel 5th Edition Chapter 3

$Nu_{D}=0.26 \times (6.14 \times 10^{6})^{0.6} \times (7.56)^{0.35}=2152.5$

The convective heat transfer coefficient can be obtained from: $Nu_{D}=0

$Re_{D}=\frac{\rho V D}{\mu}=\frac{999.1 \times 3.5 \times 2}{1.138 \times 10^{-3}}=6.14 \times 10^{6}$ $Nu_{D}=0

$\dot{Q} {cond}=\dot{m} {air}c_{p,air}(T_{air}-T_{skin})$ $Nu_{D}=0

$T_{c}=T_{s}+\frac{P}{4\pi kL}$

$h=\frac{Nu_{D}k}{D}=\frac{10 \times 0.025}{0.004}=62.5W/m^{2}K$

A 2-m-diameter and 4-m-long horizontal cylinder is maintained at a uniform temperature of 80°C. Water flows across the cylinder at 15°C with a velocity of 3.5 m/s. Determine the rate of heat transfer.